18.4 Adjoint Maps

Definition 18.4.1 (Adjoint Map).label Let $E, F$ be vector spaces over a field $K$, and $T \in \hom(E; F)$ be a linear map, then the mapping

\[T^{*}: F^{*} \to E^{*} \quad \dpn{x, T^*\phi}{E}= \dpn{Tx, \phi}{F}\]

is the algebraic adjoint of $T$.

Proposition 18.4.2.label Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$ and $T \in \hom(E; G)$, then the following are equivalent:

  1. (1)

    $T$ is $\sigma(E, F)$-$\sigma(G, H)$ continuous.

  2. (2)

    $T^{*}(H) \subset F$.

If the above holds, then

  1. (3)

    $T^{*}|_{H}$ is $\sigma(H, G)$-$\sigma(F, E)$ continuous.

  2. (4)

    $T^{**}= T$.

and the restriction of $T^{*}$ to $H$ is the adjoint of $T$ with respect to $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$.

Proposition 18.4.3.label Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$, $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, $A \subset E$, and $B \subset G$, then:

  1. (1)

    $T(A)^{\circ} = (T^{*})^{-1}(A^{\circ})$.

  2. (2)

    If $T(A) \subset B$, then $T^{*}(B^{\circ}) \subset A^{\circ}$.

Proof. (1):

\begin{align*}T(A)^{\circ}&= \bracsn{\phi \in H| \text{Re}\dpn{Tx, \phi}{\mu} \le 1 \forall x \in A}\\&= \bracsn{\phi \in H| \text{Re}\dpn{x, T^*\phi}{\lambda} \le 1 \forall x \in A}= (T^{*})^{-1}(A^{\circ})\end{align*}

(2):

\begin{align*}T^{*}(B^{\circ})&= T^{*}(\bracs{\phi \in H| \text{Re}\dpn{y, \phi}{\mu} \le 1 \forall y \in B}) \\&\subset T^{*}(\bracs{\phi \in H| \text{Re}\dpn{y, \phi}{\mu} \le 1 \forall y \in T(A)}) \\&= T^{*}(\bracs{\phi \in H| \text{Re}\dpn{Tx, \phi}{\mu} \le 1 \forall x \in A})\\&= T^{*}(\bracs{\phi \in H| \text{Re}\dpn{x, T^*\phi}{\lambda} \le 1 \forall x \in A}) \subset A^{\circ}\end{align*}

$\square$

Corollary 18.4.4.label Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$ and $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, then:

  1. (1)

    $\ker(T^{*}) = T(E)^{\perp} = \bracs{\phi \in H| \dpn{y, \phi}{\mu} = 0 \forall y \in T(E)}$.

  2. (2)

    $T^{*}$ is injective if and only if $T(E)$ is $\sigma(G, H)$-dense in $G$.

Proposition 18.4.5.label Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$, $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, $\sigma \subset 2^{E}$ be a saturated ideal of $\sigma(E, F)$-bounded sets, $\tau \subset 2^{G}$ be a saturated ideal of $\sigma(G, H)$-bounded sets, then the following are equivalent:

  1. (1)

    $T^{*}$ is continuous with respect to the $\tau$-uniform topology on $H$ and the $\sigma$-uniform topology on $F$.

  2. (2)

    $T(\sigma) \subset \tau$.

Proof. (1) $\Rightarrow$ (2): Let $A \in \sigma$, then there exists $B \in \tau$ such that $T^{*}\phi(A) \subset \ol{B_K(0, 1)}$ for all $\phi \in H$ with $\phi(B) \subset \ol{B_K(0, 1)}$. In which case, $T^{*}(B^{\circ}) \subset A^{\circ}$. Assume without loss of generality that $A$ and $B$ are convex, circled, and closed. By Proposition 18.4.3 applied to $T^{*}$ and the Bipolar theorem, $T(A) \subset B$. Therefore $T(\sigma) \subset \tau$.$\square$

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