18.4 Adjoint Maps
Definition 18.4.1 (Adjoint Map).label Let $E, F$ be vector spaces over a field $K$, and $T \in \hom(E; F)$ be a linear map, then the mapping
is the algebraic adjoint of $T$.
Proposition 18.4.2.label Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$ and $T \in \hom(E; G)$, then the following are equivalent:
- (1)
$T$ is $\sigma(E, F)$-$\sigma(G, H)$ continuous.
- (2)
$T^{*}(H) \subset F$.
If the above holds, then
- (3)
$T^{*}|_{H}$ is $\sigma(H, G)$-$\sigma(F, E)$ continuous.
- (4)
$T^{**}= T$.
and the restriction of $T^{*}$ to $H$ is the adjoint of $T$ with respect to $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$.
Proposition 18.4.3.label Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$, $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, $A \subset E$, and $B \subset G$, then:
- (1)
$T(A)^{\circ} = (T^{*})^{-1}(A^{\circ})$.
- (2)
If $T(A) \subset B$, then $T^{*}(B^{\circ}) \subset A^{\circ}$.
Proof. (1):
(2):
$\square$
Corollary 18.4.4.label Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$ and $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, then:
- (1)
$\ker(T^{*}) = T(E)^{\perp} = \bracs{\phi \in H| \dpn{y, \phi}{\mu} = 0 \forall y \in T(E)}$.
- (2)
$T^{*}$ is injective if and only if $T(E)$ is $\sigma(G, H)$-dense in $G$.
Proposition 18.4.5.label Let $\dpn{E, F}{\lambda}$ and $\dpn{G, H}{\mu}$ be dualities over $K \in \RC$, $T: E \to G$ be a $\sigma(E, F)$-$\sigma(G, H)$ continuous linear map, $\sigma \subset 2^{E}$ be a saturated ideal of $\sigma(E, F)$-bounded sets, $\tau \subset 2^{G}$ be a saturated ideal of $\sigma(G, H)$-bounded sets, then the following are equivalent:
- (1)
$T^{*}$ is continuous with respect to the $\tau$-uniform topology on $H$ and the $\sigma$-uniform topology on $F$.
- (2)
$T(\sigma) \subset \tau$.
Proof. (1) $\Rightarrow$ (2): Let $A \in \sigma$, then there exists $B \in \tau$ such that $T^{*}\phi(A) \subset \ol{B_K(0, 1)}$ for all $\phi \in H$ with $\phi(B) \subset \ol{B_K(0, 1)}$. In which case, $T^{*}(B^{\circ}) \subset A^{\circ}$. Assume without loss of generality that $A$ and $B$ are convex, circled, and closed. By Proposition 18.4.3 applied to $T^{*}$ and the Bipolar theorem, $T(A) \subset B$. Therefore $T(\sigma) \subset \tau$.$\square$
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