11.3 Riemann-Stieltjes Sums and Integrals

Definition 11.3.1 (Riemann-Stieltjes Sum, [Section X.1, Lan93]). Let $[a, b] \subset \real$, $E_{1}, E_{2}, H$ be TVSs over $F \in \RC$, $E_{1} \times E_{2} \to H$ with $(x, y) \mapsto xy$ be a continuous bilinear map, and $G: [a, b] \to E_{2}$.

Let $f: [a, b] \to E_{1}$ and $(P = \seqfz{x_j}, c = \seqf{c_j}) \in \scp_{t}([a, b])$, then

\[S(P, c, f, G) = \sum_{j = 1}^{n} f(c_{j})[G(x_{j}) - G(x_{j - 1})]\]

is the Riemann-Stieltjes sum of $f$ with respect to $G$ and $(P, c)$.

Definition 11.3.2 (Riemann-Stieltjes Integral, [Section X.1, Lan93]). Let $[a, b] \subset \real$, $E_{1}, E_{2}, H$ be TVSs over $F \in \RC$, $E_{1} \times E_{2} \to H$ with $(x, y) \mapsto xy$ be a continuous bilinear map, $G: [a, b] \to E_{2}$.

Let $f: [a, b] \to E_{2}$, then $f$ is Riemann-Stieltjes integrable with respect to $G$ if the limit

\[\int_{a}^{b} f dG = \int_{a}^{b} f(t)G(dt) = \lim_{(P, c) \in \scp_t([a, b])}S(P, c, f, G)\]

exists. In which case, $\int_{a}^{b} fdG$ is the Riemann-Stieltjes integral of $G$.

The set $RS([a, b], G)$ is the vector space of all Riemann-Stieltjes integrable functions with respect to $G$.

Lemma 11.3.3 (Summation by Parts, [Proposition 1.4, Lan93]). Let $[a, b] \subset \real$, $E_{1}, E_{2}, H$ be TVSs over $F \in \RC$, $E_{1} \times E_{2} \to H$ with $(x, y) \mapsto xy$ be a continuous bilinear map, $f: [a, b] \to E_{1}$, $G: [a, b] \to E_{2}$, and $(P, c) \in \scp_{t}([a, b])$, then

\[S(P, c, f, G) + S(P', c', G, f) = f(b)G(b) - f(a)G(a)\]

where $P' = \seqfz[n+1]{y_j}= [a, c_{1}, \cdots, c_{n}, b]$ and $c' = \seqf[n+1]{d_j}= [x_{0}, \cdots, x_{n}]$.

Proof. Denote $c_{0} = a$ and $c_{n+1}= b$, then

\begin{align*}S(P, c, f, G)&= \sum_{j = 1}^{n} f(c_{j})[G(x_{j}) - G(x_{j - 1})] = \sum_{j = 1}^{n} f(c_{j})G(x_{j}) - \sum_{j = 1}^{n} f(c_{j})G(x_{j - 1}) \\&= f(c_{n})G(x_{n})- f(c_{0})G(x_{0}) + \sum_{j = 1}^{n} f(c_{j - 1})G(x_{j-1}) - \sum_{j = 1}^{n} f(c_{j})G(x_{j - 1}) \\&= f(c_{n})G(x_{n})- f(c_{0})G(x_{0}) - \sum_{j = 1}^{n} G(x_{j - 1})[f(c_{j}) - f(c_{j - 1})] \\&= f(c_{n+1})G(x_{n}) - f(c_{0})G(x_{0}) - \sum_{j = 1}^{n+1}G(x_{j - 1})[f(c_{j}) - f(c_{j - 1})] \\&= f(b)G(b) - f(a)G(a) - S(P', c', G, f)\end{align*}
$\square$

Theorem 11.3.4 (Integration by Parts). Let $[a, b] \subset \real$, $E_{1}, E_{2}, H$ be TVSs over $F \in \RC$, and $E_{1} \times E_{2} \to H$ with $(x, y) \mapsto xy$ be a continuous bilinear map.

Let $f: [a, b] \to E_{1}$ and $G: [a, b] \to E_{2}$, then $f \in RS([a, b], G)$ if and only if $G \in RS([a, b], f)$. In which case,

\[\int_{a}^{b} f dG + \int_{a}^{b} G df = f(b)G(b) - f(a)G(a)\]

Proof. Suppose that $f \in RS([a, b], G)$. Let $U \in \cn_{F}(0)$, then there exits $P_{0} = \seqfz{x_j}\in \scp([a, b])$ such that $S(P, c, f, G) - \int_{a}^{b} fdG \in U$ for all $(P, c) \in \scp_{t}([a, b])$ with $P \ge P_{0}$. Let

\[Q_{0} = [x_{0}, x_{1}, x_{1}, \cdots, x_{n}, x_{n}]\]

then for any $(Q = \seqfz[m]{y_j}, d = \seqf[m]{d_j}) \in \scp_{t}([a, b])$ with $Q \ge Q_{0}$,

\[f(b)G(b) - f(a)G(a) - \int_{a}^{b} fdG - S(Q, d, G, f) = \int_{a}^{b} fdG - S(Q', d', G, f)\]

by Lemma 11.3.3, where $d$ and $Q'$ contain $\seqfz{x_j}$. Thus $(Q', d') \ge P_{0}$, and $\int_{a}^{b} fdG - S(Q', d', G, f) \in U$.$\square$