Example 40.1.18 (The Shift).label Let $\integer \curvearrowright 2^{\integer}$ be the Bernoulli shift of $\integer$, then:

  1. (1)

    For any $x, y \in 2^{\integer}$, $y \in \ol{\integer x}$ if and only if for each $A \subset \integer$, there exists $n \in \integer$ such that $y|_{A} = nx|_{A}$. In other words, $x$ contains a copy of any segment of $y$[1].

  2. (2)

    $\integer \curvearrowright 2^{\integer}$ is point transitive, and hence topologically transitive[2].

  3. (3)
  1. Topological conditions in Bernoulli shifts translate into combinatorial information. keyboard_return
  2. It is easier to show topological transitivity: move the trees until they are disjointkeyboard_return

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