Example 40.1.18 (The Shift).label Let $\integer \curvearrowright 2^{\integer}$ be the Bernoulli shift of $\integer$, then:
- (1)
For any $x, y \in 2^{\integer}$, $y \in \ol{\integer x}$ if and only if for each $A \subset \integer$, there exists $n \in \integer$ such that $y|_{A} = nx|_{A}$. In other words, $x$ contains a copy of any segment of $y$[1].
- (2)
$\integer \curvearrowright 2^{\integer}$ is point transitive, and hence topologically transitive[2].
- (3)
- Topological conditions in Bernoulli shifts translate into combinatorial information. keyboard_return
- It is easier to show topological transitivity: move the trees until they are disjointkeyboard_return
Post a Comment