Jerry's Digital Garden

Bibliography
/Part 2: General Topology/Chapter 4: Topological Spaces/Section 4.5: Interior, Closure, Boundary

Proposition 4.5.7. Let $\seqf{X_j}$ be separable topological spaces, then $\prod_{j = 1}^{n} X_{j}$ is also separable.

Proof. Let $\seq{A_j}$ such that $A_{j} \subset X_{j}$ is countable and dense for each $1 \le j \le n$. By Proposition 4.5.6, $\prod_{j = 1}^{n} A_{j}$ is countable and dense in $\prod_{j = 1}^{n} X_{j}$.$\square$

Direct References

  • Proposition 4.5.6

Direct Backlinks

  • Section 15.2: Product $\sigma$-Algebras
  • Proposition 15.2.3
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Jerry's Digital Garden

Bibliography

Direct References

  • Proposition 4.5.6

Direct Backlinks

  • Section 15.2: Product $\sigma$-Algebras
  • Proposition 15.2.3
Powered by Spec