Example 41.3.13.label Let $A$ be a $C^{*}$-algebra, $y, z \in A$, $\phi: A \to A$ be defined by $x \mapsto yxz$, then

  1. (1)

    $\phi$ is completely bounded.

  2. (2)

    If $y = z^{*}$, then $\phi$ is completely positive.

Proof. (1): For each $n \in \natp$ and $T \in M_{n}(A)$,

\[\phi_{n}(T) = (1_{M_n(\complex)}\otimes y)T(1_{M_n(\complex)}\otimes z)\]

$\square$

Post a Comment

Name:Email:
Please enter the tag of the current page (1JP) to post the comment.
Tag: