Definition 32.3.3 (GNS Triple (Locally Compact Group)).label Let $G$ be a locally compact group and $\phi \in L^{1}(G; \complex)^{*}$ be a positive linear functional. For each $f, g \in L^{1}(G; \complex)$, let

\[\dpn{f, g}{\phi}= \dpn{g^* * f, \phi}{L^1(G; \complex)}\]

Let $N_{\phi} = \bracsn{f \in L^1(G; \complex)| \dpn{f, f}{\phi} = 0}$, $H_{\phi}^{0} = L^{1}(G; \complex)/N_{\phi}$, $H_{\phi}$ be its completion with respect to $\dpn{\cdot, \cdot}{\phi}$, and

\[\pi_{\phi}^{0}: G \to B(H_{\phi}^{0}) \quad \pi_{\phi}^{0}(x)(f + N_{\phi}) = L_{x}f + N_{\phi}\]

For each $x \in G$, let $\pi_{\phi}(x)$ be the continuous extension of $\pi_{\phi}^{0}(x)$ to an element of $B(H_{\phi})$, then:

  1. (1)

    $H_{\phi}$ equipped with the continuous extension of $\dpn{\cdot, \cdot}{\phi}$ is a Hilbert space.

  2. (2)

    $(H_{\phi}, \pi_{\phi})$ is a well-defined unitary representation of $G$.

Let $\pi_{\phi}: L^{1}(G; \complex) \to B(H_{\phi})$ also denote the *-representation of $L^{1}(G; \complex)$ determined by $\pi_{\phi}$, then:

  1. (3)

    For each $f, g \in L^{1}(G; \complex)$, $\pi_{\phi}(f)(g + N_{\phi}) = f * g + N_{\phi}$.

  2. (4)

    There exists a cyclic vector $\xi_{\phi} \in H_{\phi}$ for $\pi_{\phi}$ such that for each $f, g \in L^{1}(G; \complex)$,

    \[\dpn{f, g}{\phi}= \dpn{\pi_\phi(f)\xi_\phi, \pi_\phi(g)\xi_\phi}{H_\phi}\]

  3. (5)

    For each $x \in G$, let $\Phi(x) = \dpn{\pi_\phi(x)\xi_\phi, \xi_\phi}{H_\phi}$, then $\Phi \in BC(G; \complex)$ and

    \[\dpn{f, \phi}{L^1(G; \complex)}= \int_{G} f(x)\Phi(x)dx\]

    for all $f \in L^{1}(G; \complex)$.

Moreover,

  1. (U)

    Let $(K, \tau)$ be a unitary representation of $G$ with cyclic vector $\eta$ such that $\dpn{\pi_\phi(x)\xi_\phi, \xi_\phi}{H_\phi}= \dpn{\tau(x)\eta, \eta}{K}$, then there exists a unitary equivalence $U: H_{\phi} \to K$ such that $U\xi_{\phi} = \eta$.

The representation $(H_{\phi}, \pi_{\phi})$ is the unitary cyclic representation of $G$ induced by $\phi$, and the triple $(H_{\phi}, \pi_{\phi}, \xi_{\phi})$ is the Gelfand-Naimark-Segal (GNS) triple associated with $\phi$.

Proof, [Theorem 3.20, Fol16]. (1): Since $\phi$ is positive, $\dpn{\cdot, \cdot}{\phi}$ is a pseudo inner product, and $H_{\phi}$ equipped with its continuous extension is a Hilbert space.

(2): By the Cauchy-Schwarz inequality, for any $f, g \in L^{1}(G; \complex)$,

\[|\dpn{f, g}{\phi}| \le \dpn{f, f}{\phi}^{1/2}\cdot \dpn{g, g}{\phi}^{1/2}\]

In particular, if $g \in N_{\phi}$, then

\begin{align*}\dpn{f * g, f * g}{\phi}&= \dpn{g^* * f^* * f * g, \phi}{L^1(G; \complex)}\\&= \dpn{g^** (f^**f*g), \phi}{L^1(G; \complex)}= \dpn{f^**f*g, g}{\phi}\end{align*}

so $N_{\phi}$ is a left ideal of $L^{1}(G; \complex)$. Let $x \in G$, then $(L_{x}g)^{*} = L_{-x}g^{*}$, and

\begin{align*}\dpn{L_xf, L_xg}{\phi}&= \dpn{(L_xg)^* * L_xf, \phi}{L^1(G; \complex)}= \dpn{(L_{-x}g^*) * (L_xf), \phi}{L^1(G; \complex)}\\&= \dpn{g^* * f, \phi}{L^1(G; \complex)}= \dpn{f, g}{\phi}\end{align*}

by Proposition 31.4.9. Therefore $\pi_{\phi}^{0}(x)$ extends to a unitary map on $H_{\phi}$, and $\pi_{\phi}$ is a well-defined unitary representation of $G$, which is strong-operator continuous by continuity of translation.

(3): Let $f, g, h \in L^{1}(G; \complex)$, then after passing through Riemann sums,

\begin{align*}\dpn{\pi_\phi(f)g + N_\phi, h + N_\phi}{H_\phi}&= \int_{G} f(x)\dpn{\pi_\phi(x)g + N_\phi, h + N_\phi}{H_\phi}dx \\&= \int_{G} f(x)\dpn{L_xg, h}{\phi}dx = \dpn{f * g, h}{\phi}\\&= \dpn{f * g + N_\phi, h + N_\phi}{H_\phi}\end{align*}

As the above holds for all $h \in L^{1}(G; \complex)$, $\pi_{\phi}(f)(g + N_{\phi}) = f * g + N_{\phi}$.

(4): Using Proposition 31.4.10, let $\angles{\psi_\alpha}_{\alpha \in A}\subset L^{1}(G; \complex)$ be an approximate identity, and $\xi_{\phi} \in H_{\phi}$ be defined by

\[\dpn{\xi_\phi, g + N_\phi}{H_\phi}= \lim_{\alpha \in A}\dpn{\psi_\alpha, g}{\phi}\quad \forall g \in L^{1}(G; \complex)\]

then $\normn{\xi_\phi}_{H_\phi}\le \norm{\phi}_{L^1(G; \complex)^*}^{1/2}$. Moreover, for any $f, g \in L^{1}(G; \complex)$,

\begin{align*}\dpn{\pi_\phi(f)\xi_\phi, \pi_\phi(g)\xi_\phi}{H_\phi}&= \lim_{\alpha \in A}\dpn{\pi_\phi(f)(\psi_\alpha + N_\phi), \pi_\phi(g)\xi_\phi}{H_\phi}\\&= \lim_{\alpha \in A}\dpn{f * \psi_\alpha + N_\phi, \pi_\phi(g)\xi_\phi}{H_\phi}\\&= \dpn{f + N_\phi, \pi_\phi(g)\xi_\phi}{H_\phi}= \dpn{f + N_\phi, g + N_\phi}{H_\phi}\end{align*}

$\square$

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